Question

我有一个任务来编写一个程序，该程序将高速公路编号作为输入，并输出高速公路是主要还是辅助，向东 / 向西，向北 / 向南，如果它是辅助的，它服务于什么主要高速公路。

highway_number = int(input(''))
if highway_number >= 1 and highway_number <= 99:
    prim = 'is primary,'
    if (highway_number % 2) == 0:
        print('I-', highway_number, prim, 'going east/west.')
    else:
        print('I-', highway_number, prim, 'going north/south.')
elif highway_number >= 100 and highway_number <= 999:
    aux = 'is auxiliary,'
    if (highway_number % 2) == 0:
        print('I-', highway_number, aux, 'serving I- %d, going east/west.' % (highway_number%100))
    else:
        print('I-', highway_number, aux, 'serving I- %d, going north/south.' % (highway_number%100))
else:
    print(highway_number, 'is not a valid interstate highway number.')

But if I run it. It adds a space between the "I-" and the highway number.

0

Answer 1

您的问题在于您打印的部分：使用print(string, string)您写出 2 个单独的刺痛，默认情况下，python 将由空格分隔。您将不得不附加字符串，这可以通过 aprint(string + string)轻松完成。一定要先使用str(top)解析数字等。

对于第二部分，在 I-和数字之间打印一个空格，因为在您的字符串中您有一个空格I- %d。Yust 将其更改为I-%d

希望这有助于：D

在完成

highway_number = int(input(''))
if highway_number >= 1 and highway_number <= 99:
    prim = 'is primary,'
    if (highway_number % 2) == 0:
        print('I-' + str(highway_number), prim, 'going east/west.')
    else:
        print('I-' + str(highway_number), prim, 'going north/south.')
elif highway_number >= 100 and highway_number <= 999:
    aux = 'is auxiliary,'
    if (highway_number % 2) == 0:
        print('I-' + str(highway_number), aux, 'serving I-%d, going east/west.' % (highway_number%100))
    else:
        print('I-' + str(highway_number), aux, 'serving I-%d, going north/south.' % (highway_number%100))
else:
    print(highway_number, 'is not a valid interstate highway number.')

Answer 2

试试这个

print('I-'+str(highway_number),prim,'going east/west.')

和

print('I-'+ str(highway_number),aux,'serving I-%d,going east/west.' % (highway_number%100))

Answer 3

这个答案的问题已经改变，增加了新的要求，增加了新的部分，以帮助其他人寻找相同的答案。

highway_number = int(input())
if highway_number >= 1 and highway_number <= 99:
    prim = "is primary,"
    if (highway_number % 2) == 0:
        print('I-' + str(highway_number), prim, 'going east/west.')
    else:
        print('I-' + str(highway_number), prim, 'going north/south.')
elif highway_number >= 100 and highway_number <= 999:
    aux = 'is auxiliary,'
    if highway_number % 100 == 0:
        print(highway_number, 'is not a valid interstate highway number.')
    elif (highway_number % 2) == 0:
        print('I-' + str(highway_number), aux, 'serving I-%d, going east/west.' % (highway_number%100))
    else:
        print('I-' + str(highway_number), aux, 'serving I-%d, going north/south.' % (highway_number%100))
else:
    print(highway_number, 'is not a valid interstate highway number.')