Question

我有一个 6 列的数据框：

- location id 1
- latitude 1
- longitude 1
- location id 2
- latitude 2
- longitude 2

我想以英里为单位计算每个 2 点之间的距离,并将其添加为新列。我正在努力寻找一个这样做的函数。我找到的最接近的是 here:s://blog.exploratory.io/calculating-distances-between-two-geo-coded-locations-358e65fcafae但它失败,因为它找不到一个名为 'list_extract' 的函数。

以下是数据示例：

structure(list(df1_location_number = c(5051, 5051, 5051, 5051, 
5051), df1_Latitude = c(34.7171375, 34.7171375, 34.7171375, 34.7171375, 
34.7171375), df1_Longitude = c(-118.9107316, -118.9107316, -118.9107316, 
-118.9107316, -118.9107316), df2_location_number = c(3051, 3085, 
3022, 3041, 3104), df2_Latitude = c(34.7171375, 39.53404, 31.626788, 
35.247982, 39.33425), df2_Longitude = c(-118.9107316, -93.292373, 
-88.330116, -84.804119, -123.713064)), row.names = c(NA, 5L), class = "data.frame")

有什么建议吗？

3

Answer 1

library(geodist)是一个很好的＆ amp;用于计算距离的快速库，并且geodist_vec()函数被矢量化以处理数据的“列”

library(geodist)
## calcualte distance in metres using Haversine formula
df$dist_m <- geodist::geodist_vec(
  x1 = df$df1_Longitude
  , y1 = df$df1_Latitude
  , x2 = df$df2_Longitude
  , y2 = df$df2_Latitude
  , paired = TRUE
  , measure = "haversine"
)
## convert to miles
df$dist_miles <- df$dist_m / 1609
#   df1_location_number df1_Latitude df1_Longitude df2_location_number df2_Latitude df2_Longitude    dist_m dist_miles
# 1                5051     34.71714     -118.9107                3051     34.71714    -118.91073       0.0     0.0000
# 2                5051     34.71714     -118.9107                3085     39.53404     -93.29237 2327593.8  1446.6089
# 3                5051     34.71714     -118.9107                3022     31.62679     -88.33012 2859098.6  1776.9413
# 4                5051     34.71714     -118.9107                3041     35.24798     -84.80412 3095858.6  1924.0886
# 5                5051     34.71714     -118.9107                3104     39.33425    -123.71306  667849.7   415.0713