Question

需要一个只有 javascript 的工作代码，没有额外的库文件（-& gt;jquery，...）从整个网页截图。

目前我有这个不工作为什么？

<script type="text/javascript">
document.addEventListener('DOMContentLoaded', function () {
var window = document.getElementById('item');
var canvas = document.getElementById('my-canvas');
var ctx = canvas.getContext("2D");
ctx.drawImage(window, 0,0, 100, 200, "rgb(255,255,255)");
canvas.toDataURL("image/png");
});
</script>
</head>
<body id="item">
test website
<canvas id='my-canvas'></canvas>

2

0

Answer 1

这并不容易，但对于其他人来说，看看浏览器引擎。因为感谢使用 blob（请克隆整个网页）。

urlsToAbsolute(document.images);
urlsToAbsolute(document.querySelectorAll("link[rel='stylesheet']"));
urlsToAbsolute(document.scripts);
var screenshot = document.documentElement.cloneNode(true);
var blob = new Blob([screenshot.outerHTML], {type: 'text/html'});
window.open(window.URL.createObjectURL(blob));
screenshot.dataset.scrollX = window.scrollX;
screenshot.dataset.scrollY = window.scrollY;
screenshot.style.pointerEvents = 'none';
screenshot.style.overflow = 'hidden';
screenshot.style.userSelect = 'none';
var script = document.createElement('script');
script.textContent = '(' + addOnPageLoad_.toString() + ')();';
screenshot.querySelector('body').appendChild(script);
window.addEventListener('DOMContentLoaded', function(e) {
    var scrollX = document.documentElement.dataset.scrollX || 0;
    var scrollY = document.documentElement.dataset.scrollY || 0;
    window.scrollTo(scrollX, scrollY);
});

我发现你可以在铬项目中阅读更多：http://www.html5rocks.com/en/tutorials/streaming/screenshare/