中科大教务系统:TXT文件中科学符号的负值(negative numbers scientific notation)-边看边学

我有一个混合浮点数作为字符串表示列表的 TXT 文件。当我将每个元素转换为浮点数列表时,负科学值不会出现在新列表中。例如,当我有以下值时:

line1 : [119.       114.        67.       117.706474 113.051278  69.933043]
line2 : [ 1.20000000e+02  0.00000000e+00  6.70000000e+01  1.20217686e+02
line3 : -8.89000000e-04  7.03216110e+01]

我的输出是

line1 : [119.       114.        67.       117.706474 113.051278  69.933043]
line2 : [ 1.20000000e+02  0.00000000e+00  6.70000000e+01  1.20217686e+02]

正如你所看到的输出不显示从负值开始的数字。

input_file = open('file.txt', 'r')
output_file = "new_file.txt"
lines = input_file.readlines()
#print(lines)
with open(output_file, "w") as filehandle:
  for line in lines:
      
      transformed_points = line.split('\n')
      a = transformed_points[0]
      #print(transformed_points[0].strip().replace('. ',','))
      a = a.replace('[', '').replace(']', '')
      floats = [float(x) for x in a.split()]
      filehandle.write(str(floats[3:5])+' \n')

这不是最干净的实现，但它可以工作。
您可以将其用作处理原始数据行的函数。

input_file = open('file.txt', 'r')
output = 'new_file.txt'
lines = input_file.read() 
# print(lines)
add = False
newlines=[]
for char in lines:
    if char == '[':
        add=True
        line = []
        continue
    if char ==']':
        add=False
        newlines.append(''.join(line))
        continue
    if char == '\n': continue
    if add == True: line.append(char)
newlines_float = [list(map(float,line.split())) for line in newlines]
for i in newlines_float:
   print(i)
input_file.close()
# the output of this is a nested list with float numbers.
# You can use f-string formatting to properly output this as you wish.

此输出

[119.0, 114.0, 67.0, 117.706474, 113.051278, 69.933043]
[120.0, 0.0, 67.0, 120.217686, -0.000889, 70.321611]

我认为 input_files 的示例字符串由 3 行组成

line1 : '[119.       114.        67.       117.706474 113.051278  69.933043]'
line2 : '[ 1.20000000e+02  0.00000000e+00  6.70000000e+01  1.20217686e+02'
line3 : '-8.89000000e-04  7.03216110e+01]'

所以如果你使用